3c=c^2+32

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Solution for 3c=c^2+32 equation: 



3c=c^2+32

We move all terms to the left:

3c-(c^2+32)=0

We get rid of parentheses

-c^2+3c-32=0

We add all the numbers together, and all the variables

-1c^2+3c-32=0

a = -1; b = 3; c = -32;
Δ = b2-4ac
Δ = 32-4·(-1)·(-32)
Δ = -119
Delta is less than zero, so there is no solution for the equation

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